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Add solution for 3f

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Tobias Eidelpes 2022-06-27 13:46:20 +02:00
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exam/ex.tex
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@ -185,7 +185,11 @@
a preimage is $1/2^{55+90} = 1/2^{145}$. This is due to the fact that the a preimage is $1/2^{55+90} = 1/2^{145}$. This is due to the fact that the
first $\unit[55]{bits}$ and the last $\unit[90]{bits}$ have to be zeros. first $\unit[55]{bits}$ and the last $\unit[90]{bits}$ have to be zeros.
\item \TODO \item An adversary does not gain additional information by using inverse
queries additionally to forward queries. Forward queries have a better
probability of being successful at breaking preimage resistance and thus
an adversary should focus on that. The total probability is thus
$1/2^{101}$.
\end{enumerate} \end{enumerate}