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Add solution for 3b

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Tobias Eidelpes 2022-06-17 12:39:07 +02:00
parent 2fa33cbd82
commit a8d043a08c
1 changed files with 7 additions and 1 deletions
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exam/ex.tex
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@ -158,7 +158,13 @@
\item The chaining value size is $\unit[101]{bits}$ ($=g$) and the message \item The chaining value size is $\unit[101]{bits}$ ($=g$) and the message
block size is $655-101=\unit[554]{bits}$. block size is $655-101=\unit[554]{bits}$.
\item \TODO \item If the message is of size $|M|=\unit[1234567]{bits}$ and the block
size is $\unit[554]{bits}$, we need $\frac{1234866}{554}=2229$ blocks with
a padding of $1234866-1234567=\unit[299]{bits}$. Additionally, the
message length is also encoded in a $\unit[554]{bit}$ block and so the
total number of blocks is $2230$. The total number of blocks corresponds
to the total number of evaluations needed, which is $2230$ evaluations of
$P$.
\item \TODO \item \TODO