Add solution for 2g
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number of evaluations an attacker has to make to obtain a repeated nonce
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is $2^{96/2} = 2^{48}$.
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\item \TODO
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\item After $2^b = 2^{62}$ forgery attempts, the attacker has exhausted the
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keyspace of the tag because the tag $T$ is of size $\unit[62]{bits}$. The
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distinguisher checks continuously if the current tag matches the
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ciphertext. If it does not, the tag is incremented by one until $2^{62}$
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queries have been made. Eventually, the distinguisher will get the valid
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tag and is then able to identify if it is in the real world or in the
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ideal world.
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\item \TODO
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