From f4a59983fc73f7686db93351d4f184076607e317 Mon Sep 17 00:00:00 2001 From: Tobias Eidelpes Date: Sat, 16 May 2020 15:26:09 +0200 Subject: [PATCH] Add proportional greedy rule --- paper/termpaper.tex | 30 ++++++++++++++++++++++++++++++ 1 file changed, 30 insertions(+) diff --git a/paper/termpaper.tex b/paper/termpaper.tex index c80d96e..e2e610b 100644 --- a/paper/termpaper.tex +++ b/paper/termpaper.tex @@ -295,6 +295,36 @@ voters that are represented by the subset. voters $v_1$ and $v_5$ and project $p_4$ voters $v_2$, $v_3$ and $v_4$. \end{example} +The third rule, which places a heavy emphasis on cost versus benefit, is similar +to the greedy rule but instead of disregarding the satisfaction per cost that a +project provides, it seeks to maximize the sum of satisfaction divided by cost +for a project $p\in P$: +\begin{equation} + \frac{\sum_{v\in V}sat(P_v,A\cup\{p\}) - \sum_{v\in V}sat(P_v,A)}{c(p)} +\end{equation} +\textcite{talmonFrameworkApprovalBasedBudgeting2019} call this type of +aggregation rule \emph{proportional greedy rule}. Example~\ref{ex:prop greedy} +shows how the outcome of a budgeting scenario might look like compared to using +a simple greedy rule or a max rule. Since the proportional greedy rule is a +variation of the simple greedy rule, it is therefore also solvable in polynomial +time. The variation of computing the satisfaction per unit of cost does not +change the complexity since it only adds an additional step which can be done in +constant time. + +\begin{example}\label{ex:prop greedy} + We again have the same set of projects $P = \{ p_2,p_3,p_4,p_5,p_6 \}$, the + same budget limit of $B = 10$ and the five voters: $v_1 = \{ p_2,p_5,p_6 + \}$, $v_2 = \{ p_2, p_3,p_4,p_5 \}$, $v_3 = \{ p_3,p_4,p_5 \}$, $v_4 = \{ + p_4,p_5 \}$ and $v_5 = \{ p_6 \}$. If we combine the satisfaction function + $sat_\#$ from equation~\ref{eq:3} with the proportional greedy rule, we get + the same result as with the simple greedy rule of $\{ p_4,p_5 \}$. While the + simple greedy rule selects first $p_5$ and then $p_4$, the proportional + greedy rule first selects $p_4$ and then $p_5$. The rule + $\mathcal{R}_{sat_\$}^p$ yields the same result as $\mathcal{R}_{sat_\$}^g$ + and $\mathcal{R}_{sat_\$}^m$ of $\{ p_4,p_5 \}$. $\mathcal{R}_{sat_{0/1}}^p$ + however, gives $\{ p_2,p_3,p_4 \}$. +\end{example} + \printbibliography \end{document}