Add solution for 5e
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\item \TODO
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\item \TODO
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\item If $G_{ch}=\phi_{ch}(G)$ and $G'=\psi(G)$, it follows that
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$G=\phi_{ch}^{-1}(G_{ch})$ and therefore $G'=\psi(\phi_{ch}^{-1}(G_{ch}))$
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so the verifier will always accept.
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\item \TODO
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